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monovalent cation reacts with OH- to form a base, the base is very strong (e.g. NaOH, KOH). Strong Acid Strong ElectrolyteStrong Base Weak Electrolyte ; Similarly, when a monovalent anion reacts with H to form an acid, the acid is a strong acid (e.g. HCl, HNO3). The monovalent molecules H2PO4-, and HCO3-, which are products of multi-charged ions
  • The figures show portions of a buret used in a titration of an acid solution of known concentration with a saturated solution of Ba(OH)2. Figures 1 and 2 show the level of the Ba(OH)2 solution at the start and the endpoint of the titration, respectively. Phenolphthalein was used as the indicator for this titration. ____ 4.
  • Correct answers: 2 question: Which substances are acids? check all that apply. 1; agoh 2; hf 3; niooh 4; nh4oh 5; hmno4 6; zn(oh)2
  • Similarly, 5.8% of NaCl in 100 mL solution º 2.9 g of NaCl in 50 mL solution. The reaction can be represented as : AgCl + NaNO3 AgNO3 + NaCl Initial 8.45/170 2.9/58.5 mole = 0.049 = 0.049 Final moles 0 0 0 0 0.049 0.049 \ Mass of AgCl precipitated = 0.049 × 143.3 = 7.02 » 7 g (a) : Mass of 1 mol (6.022 × 1023 atoms) of carbon
Ag(CN)2-(aq) OH -(aq) 0 - 2 2 e - To balance electrons we must put a 4 in front of the Ag, since each oxygen looses two electrons, and they come two at a time! That requires us to put a 4 in front of the silver complex, yielding 8 cyanide ions. 4 Ag(s) 8 CN -(aq) O2 (g) 4 Ag(CN)2-(aq) OH -(aq) We have no hydrogen on the reactant side

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CHAPTER- 2. ACIDS, BASES AND SALTS. GIST OF THE LESSON. Acids are sour in taste, turn blue litmus red, and dissolve in water to release H+ ions e.g. HCl, H2SO4, HNO3 etc. Bases are bitter in taste, have soapy touch, turn red litmus blue and give hydroxide ions in solution. e.g. NaOH, KOH etc. Ca(OH)2 Slaked lime Milk of lime Calcium hydrate Antacid, Saponifying agent Ca(C3H5O3)2 Ca lactate Ca supplement CaHPO4 • 2H2O Source of Ca and PO4 CaO lime, quicklime, calx Component of Bordeux mixture, Insecticide Ca3(PO4)2 Bone ash Antacid CaClO CaSO4 • ½ H2O or 2 H2O D. STRONTIUM 1. SrCl2 Jschlatt twitter

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3_asam_basa.ppt - Free ebook download as Powerpoint Presentation (.ppt), PDF File (.pdf), Text File (.txt) or view presentation slides online. The significance of separating a logarithm into these two parts is evident when you apply the logarithm laws to the logs of numbers such as 2000, and 2, and 0.000002. log 2000 = log (2 x 103) = log 2 + log 103 = 0.30103 + 3 = 3.30103 log 2 = log (2 x 10°) = log 2 + log 10° = 0.30103 + 0 = 0.30103 log 0.000002 = log (2 x 10-8) = log 2 + log 1Q ... Hsm tipping point review

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